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Ion Electron Method

Complete and ...

Question

Complete and balance the following compound. Acidic solution of $F e^{2 +}$ ion gives a brown ring when it comes in contact with $N O^{-} 3$ ion. Complete the following reaction of this process.
$[F e (H_{2} O)_{6}]^{2 +} + N O_{3}^{-} + H^{+} \to$ _______ $+ [F e (H_{2} O)_{6}]^{3 +} + H_{2} O$ .

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Solution

Complete and balanced reaction is:
$[F e (H_{2} O)_{6}]^{+ 2} + N O_{3}^{-} + 4 H^{-} ⟶ [F e (H_{2} O)_{5} (N O)]^{+ 2} + 3 H_{2} O$
Check for number of respective atoms on both sides.

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F e^{2 +}

N O_{3}^{-}

[F e (H_{2} O)_{6}]^{2 +} +

\to

+ H_{2} O

{_{3}}^{-}

_{2}

_{6}

^{2 +}

{_{3}}^{-}

^{+}

\to

_{2}

_{6}

^{3 +}

_{2}

_{2}

_{6}

^{2 +}

\to

_{2}

A s_{2} S_{3} + N O_{3}^{-} + H^{+} + H_{2} O \to H_{3} A s O_{4} + N O + S

{N O}_{3}^{-}

[{F e (H_{2} O)}_{6}]^{2 +} + {N O}_{3}^{-} + H^{+} ⟶ (a) + {F e (H_{2} O)}_{6}]^{3 +} + H_{2} O

[{F e (H_{2} O)}_{6}]^{2 +} + (b) ⟶ (c) + H_{2} O

[F e (H_{2} O)_{5} N O]^{2 +}

H g S + C l^{-} + H^{+} + N O_{3}^{-} \to H g C l_{4}^{2 -} + S + N O + H_{2} O

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