Question

Complete the following equations :
(a) ${}_{11}^{23}\text{Na}{+}_2^4\text{He}{\to }_{12}^{26}\text{Mg}+?$ (b) ${}_{29}^{64}\text{Cu}\to {\beta }^{+}+?$
(c) ${}^{106}\text{Ag}{\to }^{106}\text{Cd}+?$ (d) ${}_5^{10}\text{B}{+}_2^4\text{He}{\to }_7^{13}\text{N}+?$

• A. (a) ${}_1{H}^1$, (b) ${}_{28}N{i}^{64}$, (c) ${}_{-1}{\beta }^0$, (d) ${}_0{n}^1$,
• B. (a) ${}_2{H}^2$, (b) ${}_{64}N{u}^1$, (c) ${}_{-1}{\beta }^1$, (d) ${}_1{n}^{-1}$,
• C. (a) ${}_2{H}^1$, (b) ${}_{63}N{u}^2$, (c) ${}_{-1}{\beta }^0$, (d) ${}_2{n}^{-1}$,
• D. None of these

Answer 1

The correct option is A (a) ${}_1{H}^1$, (b) ${}_{28}N{i}^{64}$, (c) ${}_{-1}{\beta }^0$, (d) ${}_0{n}^1$,

(a) ${}_{11}^{23}\text{Na}{+}_2^4\text{He}{\to }_{12}^{26}\text{Mg}{+}_Z^{A}X$
$12+Z=11+2$
$Z=1$
$23+4=26+A$
$A=1$
Hence, ${}_{11}^{23}\text{Na}{+}_2^4\text{He}{\to }_{12}^{26}\text{Mg}{+}_1^{1}H$

(b) ${}_{29}^{64}\text{Cu}\to {\beta }^{+}{+}_Z^{A}X$
$29=+1+Z$
$Z=28$
$64=0+A$
$A=64$
${}_{29}^{64}\text{Cu}\to {\beta }^{+}{+}_{28}^{64}Ni$

(c) ${}_{47}^{106}\text{Ag}{\to }_{48}^{106}\text{Cd}{+}_Z^{A}X$
$47=48+Z$
$Z=-1$
$106=106+A$
$A=0$
Hence,${}_{47}^{106}\text{Ag}{\to }_{48}^{106}\text{Cd}{+}_{-1}^0\beta$

(d) ${}_5^{10}\text{B}{+}_2^4\text{He}{\to }_7^{13}\text{N}{+}_Z^{A}X$
$5+2=7+Z$
$Z=0$
$10+4=13+A$
$A=1$
${}_5^{10}\text{B}{+}_2^4\text{He}{\to }_7^{13}\text{N}{+}_0^{1}n$