In the equation a x-b y-c-0- if y-c x-d-b then x-A- d-c -a-cB- a-c -d-cC- -d-c -a-cD- None of these

The correct option is C ( d c)/(a+c) Given ax+by+c=0, Also given y= (cx+d)/b, substitute this in ax+by+c=0 We get ax+ [b (cx + d)/b]+c=0 So ax+cx+d+c=0 (a+c)x= ...

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Standard X

Mathematics

Method of Substitution to Find the Solution of a Pair of Linear Equations

In the equati...

Question

In the equation ax+by+c=0, if y= $\frac{(c x + d)}{b}$ then x =

(d+c)/(a+c)

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(-d-c)/(a+c)

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(a+c)/(d+c)

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None of these

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Solution

The correct option is B
(-d-c)/(a+c)

Given ax+by+c=0,

Also given y= $\frac{(c x + d)}{b}$ , substitute this in ax+by+c=0

We get ax+ [b $\frac{(c x + d)}{b}$ ]+c=0

So ax+cx+d+c=0

(a+c)x=-d-c

Therefore x= $\frac{- d - c}{a + c}$

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Similar questions

Q. Given that,

y = \frac{(c x + d)}{b}

; where,

b \neq 0 & (a + c) \neq 0

,

then, what is the value of x, if

a x + b y + c = 0 ?

In the equation $a x + b y + c = 0$ , if y= $\frac{(c x + d)}{b}$ and a = d, then what is the value of ' $x$ ' ?

$G i v e n t h a t y = \frac{(c x + d)}{b}$ ;

then, what is the value of x, in $a x + b y + c = 0$

if $b \neq 0 & (a + c) \neq 0$ ,

Given that $y = \frac{(c x + d)}{b}$ ;

where $b \neq 0 & (a + c) \neq 0$ ,

then, what is the value of x, if $a x + b y + c = 0$ ?

In the equation $a x + b y + c = 0$ , if y= $\frac{(c x + d)}{b}$ and a = d, then what is the value of ' $x$ ' ?

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In the equation ax+by+c=0, if y= (cx+d)b then x =

The correct option is B (-d-c)/(a+c) Given ax+by+c=0, Also given y= (cx+d)b, substitute this in ax+by+c=0 We get ax+ [b (cx+d)b]+c=0 So ax+cx+d+c=0 (a+c)x=-d-c Therefore x= −d−ca+c

In the equation ax+by+c=0, if y= $\frac{(c x + d)}{b}$ then x =

The correct option is B
(-d-c)/(a+c)

Given ax+by+c=0,

Also given y= $\frac{(c x + d)}{b}$ , substitute this in ax+by+c=0

We get ax+ [b $\frac{(c x + d)}{b}$ ]+c=0

So ax+cx+d+c=0

(a+c)x=-d-c

Therefore x= $\frac{- d - c}{a + c}$