Complete the following equations and identify $A$ and $B$ .
$C_{6} H_{5} N O_{2} 6 H - ---- \to S n / H C l [A] N a N O_{2} + H C l - ------- \to [B]$

Open in App

Solution

$C_{6} H_{5} N O_{2} Nitrobenzene 6 H - ---- \to S n / H C l C_{6} H_{5} - N H_{2} Aniline N a N O_{2} + H C l - ------- \to C_{6} H_{5} - N \equiv N C l diazonium salt$
Here first nitro benzene undergoes reduction reaction to form aniline.
This aniline on reaction with $N a N O_{2} + H C l$ forms the benzene diazonium salt.
$∴ A = Aniline$
$B = Benzene diazonium salt$

Suggest Corrections

Similar questions

A

B

R - C | | O - N H_{2} B r_{2} + K O H - ------ \to [A] C H C l_{3} + K O H - -------- \to [B]

^{'} A^{'},^{'} B^{'}

^{'} C^{'}

^{'} A^{'} N a O H / C a O - ------ \to Δ^{'} B^{'} B r_{2} / A l B r_{3} - ----- \to Δ^{'} C^{'} N a / d r y e t h e r - ------- \to Δ n - B u t a n e

A R a n e y N i - ----- \to Δ B {B r}_{2} / {A l B r}_{3} - ----- \to Δ C N a / d r y e t h e r - ------- \to Δ n - B u t a n e

A

B

C H_{3} - C H_{2} - B r + A g C N Δ ⟶ A \frac{N a}{C_{2} H_{5} O H} ⟶ B

C H_{3} - C H_{2} - B r + A g C N Δ \to A \frac{N a}{C_{2} H_{5} O H} \to B

Join BYJU'S Learning Program