wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Component of a=^i^j^k perpendicular to the vector b=2^i+^j^k is?

A
13(^i+2^j+2^k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
13(^i4^j2^k)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
13(^i+4^j+2^k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
13(^i+2^j+^k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 13(^i4^j2^k)
¯a=^i^j^k
¯b=2^i+^j^k
a=aa.bb.b(¯b)
a=(^i^j^k)(^i^j^k).(2^i+^j^k)((2)2+(1)2+(1)2)2(2^i+^j^k)
a=(^i^j^k)(21+1)6(2^i+^j^k)
a=(^i^j^k)(2^i+^j^k)3
a=(3^i2^i)(3^j+^j)(3^k^k)3
a=^i4^j2^k3=13(^i4^j2^k)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Linear Combination of Vectors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon