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pH of Salts

Compound A is...

Question

Compound (A) is a greenish crystalline salt which gives the following results when tested :

(a) Addition of $B a C l_{2}$ solution to a solution of (A) results in the formation of a white precipitate (B) which is insoluble in dilute $H C l$ .
(b) On heating, water vapor and two gases (C) and (D) are liberated, leaving a red-brown residue (E).
(c) E dissolves in $c o n c . H C l$ to give a yellow solution (F).
(d) With $H_{2} S$ , the solution (F) yields a yellow-white ppt. (G) which when filtrated, leaves a greenish filtrate (H).
(e) The solution (F) gives a green solution with $S n C l_{2}$ , and when reacted with $K_{4} [F e (C N)_{6}]$ gives a blue ppt.

Thus, gases (C) and (D) are :

S O_{2}

S O_{3}

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S O_{3}

C O_{2}

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N O_{2}

M g O

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Z n O

S O_{3}

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Solution

The correct option is D $S O_{2}$ , $S O_{3}$
(A) is $F e S O_{4} \cdot 7 H_{2} O$
$\begin{matrix} F e S O_{4} g r e e n i s h c r y s t a l l i n e s a l t & + & B a C l_{2} & ⟶ & B a S O_{4} ↓ & + & F e C l_{2} (B) \end{matrix}$
$\begin{matrix} 2 F e S O_{4} & Δ - \to & F e_{2} O_{3} & + & S O_{2} & + & S O_{3} (E) & (C) & (D) \end{matrix}$
$\begin{matrix} F e_{2} O_{3} & + & 6 H C l & ⟶ & 2 F e C l_{3} & + & 3 H_{2} O (F) \end{matrix}$
$\begin{matrix} 2 F e C l_{3} & + & H_{2} S & ⟶ & 2 F e C l_{2} & + & 2 H C l & + & S (H) & (G) \end{matrix}$
$2 F e C l_{3} + S n C l_{2} ⟶ 2 F e C l_{2} + S n C l_{4}$
$\begin{matrix} 4 F e C l_{3} & + & 3 K_{4} F e (C N)_{6} & ⟶ & F e_{4} [F e (C N)_{6}]_{3} & + & 13 K C l P r u s s i a n B l u e \end{matrix}$
( $F e C l_{3}$ gives blood-red coloration with thiocyanate ion.)
$\begin{matrix} F e C l_{3} & + & 3 K S C N & ⟶ & F e (S C N)_{3} & + & 3 K C l P o t a s s i u m & B l o o d r e d t h i o c y a n a t e & c o l o r a t i o n \end{matrix}$

Thus, from the above reaction, the correct option is A.

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Similar questions

Q. A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
(E) dissolves in warm concentrated HCl to give a yellow solution (F).

With H

_{2}

S, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H).

What is compound H?

Q. A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).

(E) dissolves in warm concentrated HCl to give a yellow solution (F).

what is F?

Q. An aqueous solution of salt (A), gives white crystalline precipitate (B) with

N a C l

solution. The filtrate gives a black precipitate (C) when

H_{2} S

is passed through it. Compound (B) is dissolves in hot water and the solution gives a yellow precipitate (D) on treating with

N a I

and cooling. The compound (A) does not give any gas with dilute

H C l

but liberates reddish brown gas on heating.

Compound (A) is _________.

Q. A white amorphous powder (A) when heated gives a colourless gas (B), which turns lime water milky and the residue (C) which is yellow when hot but white when cold. The residue (C) dissolves in dilute HCl and the resulting solution gives a white precipitate on addition of potassium ferrocyanide solution. (A) dissolves in dilute HCl with the evolution of a gas which is identical in all respects with (B). The solution of (A) as obtained above gives a white precipitate (D) on addition of excess of

N H_{4} O H

and on passing

H_{2} S

. Another portion of this solution gives initially a white precipitate (E) on addition of NaOH which dissolves in excess of it. Compounds (A) to (D) are identified as:
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Z n C O_{3}

, (B) :

C O_{2}

, (C) :

Z n O

, (D) :

Z n S

and (E) :

Z n (O H)_{2}

If true enter 1, else enter 0.

Q. Metal nitrate

(A)

on heating decomposes, leaving a residue

(B)

which goes into the solution with dil.

H C l

. The solution of

(B)

gives a white ppt. with an ammonium carbonate solution. Ppt.

C

dissolves in dil.

H C l

and the solution is treated with potassium chromate to yellow ppt.

(D)

. Solution

V

with dil.

H_{2} S O_{4}

also gives white ppt.

(E)

insoluble in dil.

H C l

and nitric acid. Precipitate

(E)

is part of white pigment lithopone.

The yellow precipitate

(D)

is:

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