Compound formed by $s p^{3}$ dhybridization will have structure

Planar

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Pyramidal

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Angular

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Trigonal bipyramidal

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Solution

The correct option is D
Trigonal bipyramidal

Structure of $s p^{3}$ d hybridized compound is Trigonal bipyramidal.

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Similar questions

s p^{3} d

s p^{3} d^{2}

What hybrid orbitals will form the following compound H₃C-CH=CH-CH₂-CH₃

N (C H_{3})_{3}

N (S i H_{3})_{3}

s p^{3} -

N -

{s p}^{3} - {s p}^{3}

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