Question

Compound with the geometry square pyramidal and $s{p}^3{d}^2$ hybridisation is:

• A. $XeO{F}_2$
• B. $XeO{F}_4$
• C. $Xe{O}_4$
• D. $Xe{O}_2{F}_2$

Answer 1

The correct option is B $XeO{F}_4$

Hybridization of an atom is identified by calculating the sum of sigma bonds and lone pairs.

If a sum of sigma bonds and lone pairs is 2 $sp$ hybridization

If a sum of sigma bonds and lone pairs is 3 $s{p}^2$ hybridization

If a sum of sigma bonds and lone pairs is 4 $s{p}^3$ hybridization

If a sum of sigma bonds and lone pairs is 2 $s{p}^{3}d$ hybridization

If a sum of sigma bonds and lone pairs is 2 $s{p}^3{d}^2$ hybridization.

So the given molecule has 5 sigma bonds 1 lone pair so the sum is 6. So its hybridization is $s{p}^3{d}^2$and the shape is square pyramidal.

Hence option B is correct.