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Question

Compound (X) (C, H, O) gives a red precipitate with cupric ions in basic medium. This compound on keeping in excess of acetic acid with some catalyst forms a polyacetal (Y). (Y) does not respond to Cu2+/OH. (X) on HIO4 oxidation forms formic acid (4 moles) and formaldehyde (1 mole only). With PhNHNH2/HCl, forms red coloured product (Z). By consuming 2 moles of the PhNHNH2/HCl, (Z) is also obtained by the given compound (W).
The compound (Y) does not give a positive test with Cu2+/OH−, because:

A
it has cyclic hemiacetal structure
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B
it has cyclic acetal type of structure which does not tautomerise into acyclic form
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C
it is an acyclic polyacetate and does not have any aldehydic group
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D
it is a ketone
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Solution

The correct option is B it has cyclic acetal type of structure which does not tautomerise into acyclic form
Since 'Y' does not give a positive test with Cu2+/OH (Felling's test). Therefore, it should not contain any aldehyde and ketone functional group.
Therefore 'Y' must have cyclic polyacetal structure which does not tautomerise into acylic form.

1013820_74949_ans_b60c149333314811a49236981152f4d2.png

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