Question

A compound 'X' with fruity smell on treatment with HCl gives two compounds Y and Z. Y has no functional isomer and Z has functional isomer. Compound 'X' does not show metamerism though its succeeding homologue has a metamer. Identify 'X', Y and Z.

Answer 1

$X\to$ ester

$Z\to$ alcohol

$Y\to$ Acid (carboxylic)

(Z) $C_2{H}_{5}OH\to$ has a functional isomer ${CH}_3-O-{CH}_3$

(Y) ${CH}_3{CH}_{2}COOH\to$ No functional isomer

(X) ${CH}_3{CH}_{2}COO{C}_2{H}_5$ do not show metamerism.