You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Raoult's Law

Compounds A a...

Question

Compounds A and B having molar mass $100 g m o l^{- 1} & 70 g m o l^{- 1}$ respectively form an ideal solution at $373 K$ .
At $373 K$ , the vapour pressures of the two liquids are $90 k P a$ and $45 k P a$ respectively.
What will be the vapour pressure of a mixture of $25 g$ of A and $35 g$ of B at $373 K$ ?

135 k P a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

67.5 k P a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60 k P a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

33 k P a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $60 k P a$
$nA=WAMA=25100=0.25 mol;nB=3570=0.5 molMole fraction of A =No. of moles of ATotal no. of moles of A and BxA=0.250.25+0.5=13xB=1−13=23$

By Raoult's law,
$P = p_{A}^{\circ} x_{A} + p_{B}^{\circ} x_{B} P = 90 \times \frac{1}{3} + 45 \times \frac{2}{3} P = 30 + 30 = 60 k P a$

Suggest Corrections

Similar questions

Q. Heptane and octane form ideal solution. At 373 K, the vapour pressures of the two liquids are 105.2 kPa and 46.8 kPa respectively. What will be the vapour pressure, in bar, of a mixture of 25 g heptane and 35 g of octane?

Q. On mixing, heptane and octane form an ideal solution. At

373

K, the vapour pressure of the two liquid components (heptane and octane) are

105

kPa and

45

kPa respectively. Vapour pressure of the solution obtained by mixing

25

g of heptane and

35

g of octane will be : (molar mass of heptane =

100

m o l^{- 2}

and of octane =

114

m o l^{- 1}

)

Heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components are 105.2 kPa and 46.8 kPa respectively. What will be the vapour pressure of a mixture of 26.0 g of heptane and 35 g of octane?

QUESTION 2.156

Heptane and octane form an ideal solution. At 373 K, the vapour pressure of the two liquid components is 105.2 kPa and 46.8 kPa respectively. What will be the vapour pressure of a mixture of 26.0 g of heptane and 35 g of octane?

Q. The vapour pressure of a dilute aqueous solution of a non-volatile solute (molar mass

180

m o l^{- 1}

) at

373

K is

750

mm Hg. Calculate Molality.

Join BYJU'S Learning Program

Compounds A and B having molar mass 100 g mol−1& 70 g mol−1 respectively form an ideal solution at 373 K. At 373 K, the vapour pressures of the two liquids are 90 kPa and 45 kPa respectively. What will be the vapour pressure of a mixture of 25 g of A and 35 g of B at 373 K?

The correct option is C 60 kPanA=WAMA=25100=0.25 mol;nB=3570=0.5 molMole fraction of A =No. of moles of ATotal no. of moles of A and BxA=0.250.25+0.5=13xB=1−13=23 By Raoult's law, P=p∘AxA+p∘BxBP=90×13+45×23P=30+30=60 kPa