Compute each of the following:

(a) 30 + (-25) + (-10) (b) (-20) + (-5)

(c) 70 + (-20) + (-30) (d) -50 + (-60) + 50

(e) 1 + (-2) + (-3) + (-4)

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Solution

(a) 30 + (-25) + (-10) = 30 - 25 - 10 = 30 - (25+10) = 30 - 35 = -5

(b) (-20) + (-5) = -20 - 5 = -(20 + 5) = -25

(c) 70 + (-20) + (-30) = 70 - 20 - 30 = 70 - (20 + 30) = 70 - 50 = 20

(d) -50 + (-60) + 50 = -50 - 60 + 50 = -50 + 50 -60 = -60

(e) 1+ (-2) + (-3) + (-4) = 1 - 2 - 3 - 4 = 1 - (2 + 3 + 4) = 1 - 9 = -8

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Question 60

Compute each of the following:

(a) 30 + (-25) + (-10) (b) (-20) + (-5)

(e) 1 + (-2) + (-3) + (-4) (f) 0 + (-5) + (-2)

(g) 0 - (-6) - (+6) (h) 0 - 2 - (-2)

Compute mean deviation from mean of the following distribution :

$\begin{matrix} Marks & 10 - 20 & 20 - 30 & 30 - 40 & 40 - 50 & 50 - 60 & 60 - 70 & 70 - 80 & 80 - 90 No. of students & 8 & 10 & 15 & 25 & 20 & 18 & 9 & 5 \end{matrix}$

Q. From the following compute Median and Mode
No of employees Income
5 0-10
7 10-20
15 20-30
25 30-40
20 40-50
15 50-60
8 60-70
5 70-80

Compute the mode of the following distribution:

Class interval	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$
Frequency	$2$	$5$	$10$	$5$	$4$	$3$

Q. Compute the mean by short cut method of the following frequency distribution

Marks obtained	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$
Number of Students	$6$	$8$	$13$	$7$	$4$	$2$

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Compute each of the following: (a) 30 + (-25) + (-10) (b) (-20) + (-5) (c) 70 + (-20) + (-30) (d) -50 + (-60) + 50 (e) 1 + (-2) + (-3) + (-4)

Compute each of the following:

(a) 30 + (-25) + (-10) (b) (-20) + (-5)

(c) 70 + (-20) + (-30) (d) -50 + (-60) + 50

(e) 1 + (-2) + (-3) + (-4)