Compute mean deviation from mean of the following distribution :
Marks10−2020−3030−4040−5050−6060−7070−8080−90No. of students8101525201895
Computation of mean deviation from the mean
Classnumbers of studentsfiMid points xifixi|xi−¯x|=|xi−49|fi|xi−¯x|10−208151203427220−3010252502424030−4015355251421040−5025451125410050−6020551100612060−70186511701628870−809756752623480−9058542536180N=∑8i=1fi=110∑8i=1fixi=5390∑8i=1fi|xi−¯X|=1644
N=∑8i=1fi=110
and ∑8i=1fixi=5390
¯X=∑8i=1fixiN
=5390110
=49
Mean deviation ∑8i=1fi|xi−¯X|N
=1644110
=14.945
14.95