Question

Compute P (A/B), if P (B) = 0.5 and P (A ∩ B) = 0.32

Answer 1

$$\begin{gathered} \mathrm{Given}: \\ P\left(B\right)=0.5 \\ P\left(A\cap B\right)=0.32 \\ \mathrm{Now}, \\ P\left(\raisebox{1ex}{$A$}\!\left/ \!\raisebox{-1ex}{$B$}\right.\right)=\frac{P\left(A\cap B\right)}{P\left(B\right)} \\ \Rightarrow P\left(\raisebox{1ex}{$A$}\!\left/ \!\raisebox{-1ex}{$B$}\right.\right)=\frac{0.32}{0.5}=\frac{32}{50}=\frac{16}{25} \end{gathered}$$