Question

Compute P$\left(\frac{A}{B}\right)ifP\left(B\right)=0.5P(A\cap B)=0.32$

Answer 1

It is given that $P\left(B\right)=0.5andP(A\cap B)=0.32\therefore P\left(\frac{A}{B}\right)=\frac{P(A\cap B)}{P\left(B\right)}=\frac{0.32}{0.5}=\frac{32}{50}=\frac{16}{25}$