Compute the following scalar triple products: $(2 i - 3 j + k) . (i - j + 2 k) \times (2 i + j - k)$

- 14

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14

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- 16

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16

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Solution

The correct option is A $- 14$
$(2 i - 3 j + k) . (i - j + 2 k) \times (2 i + j - k) = (2 i - 3 j + k) . (i (1 - 2)) - j ((- 1) - 4) + k (1 - (- 2)) = (2 i - 3 j + k) . (- i + 5 j + 3 k) = - 2 - 15 + 3 = - 14$

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