Compute the value of $34^{2} - 6^{2}$

- 3800

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- 3600

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- 3200

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- 2200

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Solution

The correct option is C
- 3200

The given expression is

$34^{2} - 6^{2}$ which can be written as

$(34 + 66) (34 - 66) [x^{2} - y^{2} = (x + y) (x - y)]$

$= 100 \times - 32$

$= - 3200$

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Similar questions

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(x - 6)^{2}

A = ⎡ ⎢ ⎣ \begin{matrix} 151 \end{matrix} \begin{matrix} 20 - 1 \end{matrix} \begin{matrix} - 3 21 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 342 \end{matrix} \begin{matrix} - 1 20 \end{matrix} \begin{matrix} 253 \end{matrix} ⎤ ⎥ ⎦

C = ⎡ ⎢ ⎣ \begin{matrix} 401 \end{matrix} \begin{matrix} 13 - 2 \end{matrix} \begin{matrix} 223 \end{matrix} ⎤ ⎥ ⎦

(A + B)

(B - C)

A + (B - C) = (A + B) - C

Find the value using identities : $182 \times 182 - 2 \times 182 \times 62 + 62 \times 62$

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