Question

Find the value using identities : $182\times 182-2\times 182\times 62+62\times 62$

Answer 1

Given: $182\times 182-2\times 182\times 62+62\times 62$
It is given in the form of an identity which states $(a-b{)}^2=a^2-2ab+b^2$.
Here, in your question $182$ is ${}^{\prime }{a}^{\prime }$ and $62$ represents ${}^{\prime }{b}^{\prime }$.
Therefore, ${182}^2+2\times 182\times 62+{62}^2=(182-62{)}^2$
$={120}^2$
$=14400$
Hence, $182\times 182-2\times 182\times 62+62\times 62=14400$