Compute the value of (612)2−(412)2
24
22
21
25
The given expression is
(612)2−(412)2 which can be written as
=(612+412)(612−412) [a2−b2=(a+b)(a−b)]
=11×2
=22
(1) 42 + 24 − 32
(2) 33 − 22 + 20
(3) 53 − 22 + 40
(4) 61 + 50 − 41
(5) (−2)2 + 12 − 22
(1) 22 + 32
(2) 32 − 22
(3) 22 × 33 (4) (−2)2 × (1)2
(5) 12 + 52
(6) 12 + 20
(7) 70 + 12
(8) 61 − 40
(9) 100 − 20
(10) 51 × 31