Question

Compute the value of x in each of the following figure

Answer 1

Considering the, $△ABC$ (anticlockwise direction),

We can see that $\angle BAC={180}^o-{120}^o={60}^o$ (vertically opposite angle)

and $\angle ACB={180}^o-{112}^o={68}^o$ (Angle on a straight line)

Using theorem, Sum of interior angles of a triangle is ${180}^o$ .

We get $\angle A+\angle B+\angle C={180}^o$

$\Rightarrow {60}^o+x+{68}^o={180}^o$

$\Rightarrow x={180}^o-{128}^o={52}^o$