Question

Conall had a box of $36$ candy bars to sell for a class fundraiser. He sold $10$ of the bars on his own, and his mother sold half of the remaining bars to her coworkers. If no other bars were sold, what fraction of Conalls original $36$ bars remained unsold?

• A. $\frac{5}{8}$
• B. $\frac{11}{36}$
• C. $\frac{1}{3}$
• D. $\frac{13}{36}$
• E. $\frac{7}{18}$

Answer 1

The correct option is D $\frac{13}{36}$

Given:

Number of bars Conall had $=$ $36$

After selling $10$ bars on his own,

Number of bars remaining $=$ Number of bars Conall had $-$ Number of bars he sold on his own

Number of bars remaining $=$ $36$ $-$ $10$

Number of bars remaining $=$ $26$

After his mother sold ha;f of the remaining bars,

Number of bars remained unsold $=$ Number of remaining bars $-$ Number of bars his mother sold

$=$ $26$ $-$ $\frac{26}{2}$

$=$ $26$ $-$ $13$

$=$ $13$

Number ofbars remained unsold $=$ $13$

Fraction of Conalls bars remained unsold $=$ $\frac{Numberofbarsremainedunsold}{NumberofbarsConallhad}$

$=$ $\frac{13}{36}$

Therefore, Fraction of Conalls bars remained unsold is ${}^{\prime }$$\frac{13}{36}$${}^{\prime }$.