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Question

Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation each to illustrate the above-mentioned properties of sulphuric acid.


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Solution

Concentrated sulphuric acid (Conc.H2SO4) can act as both oxidizing agent and a non-volatile acid.

  • The given below reaction shows the non-volatile property of Conc.H2SO4.

NaCl(s)(Sodiumchloride)+H2SO4(l)(Sulphuricacid)NaHSO4(s)(Sulphuricbisulphate)+HCl(aq.)(Hydrochloricacid)

Here, in this reaction, sodium chloride is reacting with sulphuric acid and giving sodium bisulphate and hydrochloric acid.

  • The below-given reaction shows the oxidizing property of Conc.H2SO4

C(s)(Carbon)+2H2SO4(l)(Sulphuricacid)CO2(g)(Carbondioxide)+2H2O(l)(Water)+2SO2(g)(Sulphurdioxide)

Here in this reaction, carbon is reacting with sulphuric acid and giving carbon dioxide, water, and sulphur dioxide gas is evolved.

From the above discussion, we can conclude that:-

  • Sulphuric acid can act as a non-volatile acid. This is because sulphuric acid has high boiling points and this property makes this acid to act as a non-volatile acid.
  • Sulphuric acid can act as an oxidizing agent. This is due to the fact on thermal decomposition it yields nascent oxygen O.

H2SO4(aq)H2O(l)+SO2(g)+O(sulphuric(water)(sulphur(nascentacid)dioxide)oxygen)


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