MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equivalent, Molar Conductivity and Cell Constant

Conductance o...

Question

Conductance of ${A l}^{+ 3}$ is $x$ $S m^{2} g$ ${e q}^{- 1}$ and that of ${S O}_{4}^{- 2}$ is $y$ $S m^{2} g$ ${e q}^{- 1}$ . Molar conductance of Aliminium sulphate is _____ $S m^{2}$ ${m o l e}^{- 1}$

A

\frac{x + y}{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

x + y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

6 (x + y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2 x + 3 y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{x + y}{6}$
${A l}^{3 +} = x$ ${s m}^{2} g {e q}^{- 1}$
${S O}_{4}^{2 -} = y$ ${s m}^{2} g {e q}^{- 1}$
Aluminium sulphate $: {A l}_{2} {(S O_{4})}_{3} \to 2 {A l}^{3 +} + 3 {S O}_{4}^{2 -}$
total change on ion $= 6$
$∴$ Molar conductance $= \frac{x + y}{6}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Molar ionic conductance of

{C a}^{+ 2}

x

S m^{2}

{m o l e}^{- 1}

. Equivalent conductance of calcium phosphate is ____

S m^{2} g

{e q}^{- 1}

Q. The ionic conductances of

A l^{3 +}

S O_{3}^{2 -}

ions at infinite dilution are

x

y o h m^{- 1} c m^{2} m o l^{- 1}

respectively. If Kohlrausch's law is valid, then molar conductance of aluminium sulphate at infinite dilution will be____________.

Q. The ionic equivalent conductivities of

K^{+}

S O_{4}^{2 -}

ions are x,y and z

S c m^{2} e q^{- 1}

, respectively. Calculate

Λ_{m}^{0}

Λ_{e q}^{0}

(K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O)

Q. The ionic equivalent conductivities of

C_{2} O_{4}^{2 -}, K^{+},

N a^{+}

ions are x, y and z S

c m^{2} E q^{- 1}

respectively. Calculate

A_{e q}^{0}

(N a O O C - C O O K)

Q. Solve the following pairs of equations by reducing them to a pair of linear equations:

\frac{1}{2 x} + \frac{1}{3 y} = 2; \frac{1}{3 x} + \frac{1}{2 y} = \frac{13}{6}

\frac{2}{\sqrt{x}} + \frac{3}{\sqrt{y}} = 2; \frac{4}{\sqrt{x}} - \frac{9}{\sqrt{y}} = - 1

\frac{4}{x} + 3 y = 14; \frac{3}{x} - 4 y = 23

\frac{5}{x - 1} + \frac{1}{y - 2} = 2; \frac{6}{x - 1} - \frac{3}{y - 2} = 1

\frac{7 x - 2 y}{x y} = 5; \frac{8 x + 7 y}{x y} = 15

6 x + 3 y = 6 x y; 2 x + 4 y = 5 x y

\frac{10}{x + y} + \frac{2}{x - y} = 4; \frac{15}{x + y} - \frac{5}{x - y} = - 2

\frac{1}{3 x + y} + \frac{1}{3 x - y} = \frac{3}{4}; \frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = \frac{- 1}{8}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equivalent, Molar Conductivity and Cell Constant

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Equivalent, Molar Conductivity and Cell Constant

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon