Conjugate base of $H_{2} S O_{4}$ is:

Sulphate ion

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Bisulphate ion

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H S O_{4}^{2 -}

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S O_{4}^{-}

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Solution

The correct option is A Bisulphate ion
Conjugate Base of $H_{2} S O_{4}$

$H_{2} S O_{4} - H^{+} \to H S O_{4}^{-}$

$∴$ Bisulphate ion = $H S O_{4}^{-}$

Option B is correct.

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