Question

Conjugate base of $N{H}_3$ is:

• A. $N{H}_4^{+}$
• B. $N{H}_2^{+}$
• C. $N{H}_2^{-}$
• D. $N_2$

Answer 1

The correct option is C $N{H}_2^{-}$

Conjugate base :
Species formed by the loss of a proton from an acid is called the conjugate base of that acid.
[Conjugate base has one proton less than the acid]

When $H^{+}$ is removed from $N{H}_3$ we get $N{H}_2^{-}$.
$N{H}_3\stackrel{-H^{+}}{⟶}N{H}_2^{-}$
So, $N{H}_2^{-}$ is the conjugate base of $N{H}_3$ acid.