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Byju's Answer
Standard XII
Physics
Mechanism of Formation of P-N Junction
Consider a Bo...
Question
Consider a Boolean expression.
f
=
(
B
+
B
C
)
(
B
+
¯
¯¯
¯
B
C
)
(
B
+
D
)
The minimum number of NAND-gates required to implement this function
′
f
′
will be __________
0
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Solution
The correct option is
A
0
So, it is clear that output
′
f
′
can be directly obtained from input
′
B
′
. So, the number of NAND-gates required is zero.
Given,
f
=
(
B
+
B
C
)
(
B
+
¯
¯¯
¯
B
C
)
(
B
+
D
)
=
(
B
B
+
B
C
B
+
B
¯
¯¯
¯
B
C
+
B
C
¯
¯¯
¯
B
C
)
(
B
+
D
)
=
B
B
+
B
D
=
B
+
B
D
=
B
(
1
+
D
)
f
=
B
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2
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Q.
Minimum number of 2-input NAND gates required to implement the Boolean function given below is _______.
f
=
(
¯
¯¯
¯
A
+
¯
¯¯
¯
B
)
(
C
+
D
)
Q.
Find the minimum number of NAND gates required to implement
A
+
A
¯
B
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Q.
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4
×
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f
=
A
(
A
+
¯
¯¯
¯
B
)
(
A
+
¯
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¯
B
+
C
)
is equal to _______.
Q.
If the complements of inputs are available, minimum number of 2 input NAND gates required to realize the mentioned below function will be _______
F
(
A
,
B
,
C
,
D
)
=
B
¯
¯¯¯
¯
D
+
¯
¯¯
¯
B
C
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+
A
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C
+
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¯
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¯
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+
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¯
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