Consider a circular track of circumference = 1400 m. There are 2 bikes which start from point A and move in the opposite direction. Once they meet, they start moving in the opposite directions. The one that moves in the anticlockwise direction to the other one has a speed in the ratio of 36:48 kmph. Find the distance of the two bikes from A when they meet for the 15th time?

1200

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250

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350

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450

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Solution

The correct option is C
350

1400 m track is divided into 7 parts of 200 m each. The speeds of the two bikes are in a ratio of 3:4, each time they meet, they will cover a distance in the ratio of 3:4
They will thus meet for the first time at ${\frac{3}{4}}^{t h}$ the distance which will happen at point 4 à 1050 m. Second time they will meet at the starting point.
3 $^{r d}$ time at point 4... and so on.so the 15 $^{t h}$ time, they meet at 1050 cm which is 350 m from A

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