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Frustum of a Cone

Consider a fr...

Question

Consider a frustum of cone with larger and smaller radius equal to $r_{1} a n d r_{2}$ , respectively. Then, the total surface area of frustum of a cone is $π l (r_{1} + r_{2}) + π (r_{1}^{2} + r_{2}^{2})$ . if correct enter 1 else enter 0

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Solution

Total surface area of frustum of a cone is $π l (r_{1} + r_{2}) + π (r_{1}^{2} + r_{2}^{2})$

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Similar questions

Q. Consider a frustum of cone with larger and smaller radius equal to

r_{1} a n d r_{2}

, respectively. Then, volume of frustum of a cone is

\frac{1}{3} π h (r_{1}^{2} + r_{2}^{2} + r_{1} r_{2})

.

State whether the statement is True or False.

Q. State True(1) or False(0).

The curved surface area of a frustum of a cone is

π l (r_{1} + r_{2})

l = \sqrt{h^{2} + {(r_{1} - r_{2})}_{1}^{2}}

r_{1} a n d r_{2}

are the radii of the two ends of the frustum and

h

is the vertical height.

Total surface area of frustum of cone
=

π l (r_{1} + r_{2}) + π {r_{1}}^{2} + π {r_{2}}^{2}

Q. The total surface area of frustum cone is

1200 f t^{2}

. The radius of a top cone is

3

and the bottom cone is

6

ft. What is the curved surface area of a frustum of cone?

Q. Find the surface area of a frustum of cone, whose larger and smaller radius is 10 and 2 mm. The slant height of the cone is 15 mm.

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