Consider a fusion reaction $^{4} H e$ + $4^{H} e$ = $8^{B} e$ . For the reaction Q-value is (90 + n) KeV.Find n.Take 1 amu = 930/ $c^{2}$ MeV.Atomic mass of $8^{B} e$ is 8.0053 u and that of $4^{H} e$ is 4.0026 u.

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Solution

Energy released $Q = (M_{B e} - 2 M_{H e}) \times c^{2}$

$⟹ Q = (8.0053 - 2 \times 4.0026) a m u \times c^{2}$

$⟹ Q = 0.0001 \times 930 M e V = 93 k e V$

$∴ 93 = 90 + n$
Hence, $n = 3$

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Similar questions

Q. Consider a fusion reaction

^{4} He +^{4} He \to^{8} Be .

The

Q -

value of the reaction is

- (90 + n) k eV .

The value of

n

is (integer only).
Take

1 amu = \frac{930}{c^{2}} M eV {Atomic mass of}^{8} Be = 8.0053 u;^{4} He = 4.0026 u

Q. Calculate the Q-value of the fusion reaction

^{4} H e +^{4} H e =^{8} B e

Is such a fusion energetically favorable? Atomic mass of

^{8} B e

is 8.0053 u and that of

^{4} H e

is 4.0026 u.

Q. Calculate the Q-value of the fusion reaction
⁴He + ⁴He = ⁸Be.
Is such a fusion energetically favourable? Atomic mass of ⁸Be is 8.0053 u and that of ⁴He is 4.0026 u.

Calculate the Q-value of the fusion reaction $^{4} H e +^{4} H e =^{8} B e$ Is such a fusion energetically favorable? Atomic mass of $^{8} B e$ is 8.0053 u and that of $^{4} H e$ is 4.0026 u.

Q. What is the

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of the reaction?

P +^{7} L i \to^{4} H e +^{4} H e

The atomic masses of

^{1} H,^{4} H e

and

^{7} L i

are

1.007825 u, 4.0026034 u

and

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respectively.

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Consider a fusion reaction 4He + 4He = 8Be. For the reaction Q-value is (90 + n) KeV.Find n.Take 1 amu = 930/c2MeV.Atomic mass of 8Be is 8.0053 u and that of 4He is 4.0026 u.

Energy released Q=(MBe−2MHe)×c2⟹Q=(8.0053−2×4.0026)amu×c2⟹Q=0.0001×930MeV=93keV∴93=90+nHence, n=3

Consider a fusion reaction $^{4} H e$ + $4^{H} e$ = $8^{B} e$ . For the reaction Q-value is (90 + n) KeV.Find n.Take 1 amu = 930/ $c^{2}$ MeV.Atomic mass of $8^{B} e$ is 8.0053 u and that of $4^{H} e$ is 4.0026 u.

Energy released $Q = (M_{B e} - 2 M_{H e}) \times c^{2}$

$⟹ Q = (8.0053 - 2 \times 4.0026) a m u \times c^{2}$

$⟹ Q = 0.0001 \times 930 M e V = 93 k e V$

$∴ 93 = 90 + n$
Hence, $n = 3$