What is the $Q - v a l u e$ of the reaction?
$P +^{7} L i \to^{4} H e +^{4} H e$
The atomic masses of $^{1} H,^{4} H e$ and $^{7} L i$ are $1.007825 u, 4.0026034 u$ and $7.016004 u$ respectively.

17.35 M e V

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18.06 M e V

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177.35 M e V

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170.35 M e V

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Solution

The correct option is A $17.35 M e V$
The total mass of the initial particles
$m_{i} = 1.007825 + 7.016004$
$= 8.023829 u$
and the total mass of final particles
$m_{f} = 2 \times 4.002603$
$= 8.005206 u$
Difference between initial and final mass of particles
$△ m = m_{i} - m_{f}$
$= 8.023829 - 8.005206$
$= 0.018623 u$
The $Q - v a l u e$ is given by
$Q = (△ m) c^{2}$
$= 0.018623 \times 931.5$
$= 17.35 M e V$ .

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Q

Calculate the Q-value of the fusion reaction

$^{4} H e +^{4} H e =^{8} B e$ .

Is such a fusion energetically favourable? Atomic mass of of $^{8} B e$ is 8.0053 u and that of $^{4} H e$ is 4.0026 u.

^{4} H e +^{4} H e =^{8} B e

^{8} B e

^{4} H e

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