wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider a particle of mass m suspended vertically by a string at the equator. Let R and M denote the radius and the mass of the earth respectively. If ω is the angular velocity of earth's rotation about its own axis, the tension in the string is equal to


A

GmM2R2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

GmMR2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

GmMR2mω2R

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

GmMR2+mω2R

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

GmMR2mω2R


The acceleration due to gravity at a place on the surface of the earth is given by
g=gω2R cos ϕ where ϕ is the latitude of the place.
At the equator, ϕ=0. Therefore, g=gω2R
Therefore, the tension in the string will be T=mg=mgmω2R=GmMR2mω2R
Hence, the correct choice is (c).


flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Variation in g
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon