Consider a signal, the Nyquist sampling rate for $x (t) = s i n c (200 t) s i n c^{2} (1000 t)$ is________ $s a m p l e / s e c .$
2200

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Solution

The correct option is A 2200
$X (f) = X_{1} (f) \times X_{2} (f) \times X_{3} (f)$

$f_{N s a m p l i n g} = 2 f_{m a x} = 2 (100 + 500 + 500)$
$= 2200 \frac{s a m p l e s}{s e c}$

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