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Question

Consider a square loop of side 4 cm is positioned in a uniform magnetic field of magnitude 0.5 T so that the plane of the loop makes an angle of 30 with the magnetic field. Calculate amount of flux passing through the square loop.


A
2×104 weber
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B
4×103 weber
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C
4×105 weber
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D
4×104 weber
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Solution

The correct option is D 4×104 weber
Given: l=4 cm, B=0.5 T

Here, angle 30 is the angle between the plane and the magnetic field, so the angle between the area vector and the magnetic field is θ=60.

So, using ϕ=BAcosθ

i.e. ϕ=0.5×0.04×0.04×cos60

We get,

ϕ=4×104 weber

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