Question

Consider a square loop of side $4\text{cm}$ is positioned in a uniform magnetic field of magnitude $0.5\text{T}$ so that the plane of the loop makes an angle of ${30}^{\circ }$ with the magnetic field. Calculate amount of flux passing through the square loop.

• A. $2\times {10}^{-4}\text{weber}$
• B. $4\times {10}^{-3}\text{weber}$
• C. $4\times {10}^{-5}\text{weber}$
• D. $4\times {10}^{-4}\text{weber}$

Answer 1

The correct option is D $4\times {10}^{-4}\text{weber}$

Given: $l=4\text{cm},B=0.5\text{T}$

Here, angle ${30}^{\circ }$ is the angle between the plane and the magnetic field, so the angle between the area vector and the magnetic field is $\theta ={60}^{\circ }$.

So, using $\varphi =BA\cos \theta$

i.e. $\varphi =0.5\times 0.04\times 0.04\times \cos {60}^{\circ }$

We get,

$\varphi =4\times {10}^{-4}\text{weber}$