Consider an amine having the molecular formula $C_{4} H_{11} N$
The number of structural isomers possible for the given amine are :

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Solution

Here,
$D O U = (4 + 1) - \frac{11}{2} + \frac{1}{2} D O U = 0$
So, there are no $π$ bonds and rings

There are 8 different structural isomers possible for the compound having molecular formula $C_{4} H_{11} N$ :
1. Primary Amines:

2. Secondary amines

3. Tertiary amine

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