Question

Consider another example where a pack contains $4$ blue, $2$ red and $3$ black pens. If a pen is drawn at random from the pack, replaced and the process repeated $2$ more times, What is the probability of drawing $2$ blue pens and $1$ black pen?

• A. $\frac{7}{81}$
• B. $\frac{9}{81}$
• C. $\frac{6}{81}$
• D. $\frac{16}{243}$

Answer 1

The correct option is D $\frac{16}{243}$

Here, total number of pens = $9$

Probability of drawing 1 blue pen = $\frac{4}{9}$

Probability of drawing another blue pen = $\frac{4}{9}$

Probability of drawing 1 black pen = $\frac{3}{9}$

Probability of drawing 2 blue pens and 1 black pen = $\frac{4}{9}\times \frac{4}{9}\times \frac{3}{9}=\frac{48}{729}=\frac{16}{243}$