(D) has x number of double bond equivalents, the number of double bonds in (D) is y, the number of all stereoisomers of (D) is z. What is the value of x + y + z?
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Solution
So, double bond equivalent = 11, number of double bonds = 8 and stereoisomers = 3
So, x =11, y =8, z =3 and x + y + z = 11 + 8 + 3 = 22