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Question

Consider the C program given below:

# include <stdio.h>
int main( )
{
int sum = 0, maxsum = 0, i, n = 6;
int a ( ) = {2, -2, -1, 3, 4, 2};
for (i = 0; i < n; i++)
{
if(i = = 0 | | a[i] < 0 | | a[i] < a[ i -1])
{
if (sum > maxsum)
maxsum = sum;
sum = (a[i] > 0)? a[i] : 0;
}
else sum + = a[i];
if (sum > maxsum)
maxsum =sum;
printf("%d\n", maxsum);
}
}

What is the value printed out when this program is executed?

A
9
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B
6
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C
8
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D
7
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Solution

The correct option is D 7
Syntax error in above code segment. Right code given below:

# include <stdio.h>
int main ( )
{
int sum = 0, maxsum = 0, i, n = 6;
int a[ ] = {2, -2, -1, 3, 4, 2};
for (i = 0; i , n; i++)
{
if ( i == 0 | | a[i] < 0 | | a[i] < a[i -1])
{
if (sum > maxsum)
maxsum = sum;
sum = (a[i] > 0) ? a[i] : 0;
}
else
sum + = a[i];
}
if (sum > maxsum) maxsum = sum;
printf("%d\n", maxsum);
}

Simply execute and trace value of sum and maxsum for i = 0 to 5

i initially 0 1 2 3 4 5

sum 0 0 2 0 3 7 2
maxsum 0 0 2 2 2 2 7

So, maxsum = 7

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