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Standard XII

Physics

Towards Biot-Savart Law

Consider the ...

Question

Consider the charge configuration and a spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface, the electric field will be ?

Due to

q_{2}

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Only due to the positive charges

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Due to all the charges

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Due to

+ q_{1}

and

- q_{1}

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Solution

The correct option is C Due to all the charges
The total flux linked with the closed surface is given by Gauss's law,

$ϕ = \int \to E . \to d s = \frac{Q_{e n c l}}{ε_{0}}$

So, the electric field will be due to all the charge enclosed by the surface.

The correct option is C.

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Similar questions

Q. Consider the charge configuration and spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface the electric field will be due to

Figure 20.17 shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to

Q. Assertion :Four point charges

q_{1}

q_{2}

q_{3}

and

q_{4}

are as shown in figure. The flux over the shown Gaussian surface depends only on charges

q_{1}

and

q_{2}

. Reason: Electric field at all points on Gaussian surface depends only charges

q_{1}

and

q_{2}

Q. Assertion

(A)

: Four point charges

q_{1}, q_{2}, q_{3}

and

q_{4}

are as shown in figure. The flux over the shown gaussian surface depends only on charges

q_{1}

and

q_{2}

Reason

(R)

: Electric field at all points on gaussian surface is depends only on charges

q_{1}

and

q_{2}

Select the most appropriate answer from the options given below

Q. Consider the charge configuration and a spherical Gaussian surface as shown in the figure. Find the net flux through the Gaussian surface.

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Consider the charge configuration and a spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface, the electric field will be ?

The correct option is C Due to all the chargesThe total flux linked with the closed surface is given by Gauss's law,ϕ=∫→E.→ds=Qenclε0So, the electric field will be due to all the charge enclosed by the surface.The correct option is C.

The correct option is C Due to all the charges
The total flux linked with the closed surface is given by Gauss's law,

$ϕ = \int \to E . \to d s = \frac{Q_{e n c l}}{ε_{0}}$

So, the electric field will be due to all the charge enclosed by the surface.

The correct option is C.