Question

Consider the circuit in the figure. What will be potential difference between A and B in steady state?

• A. $\epsilon$
• B. $\epsilon /2$
• C. $\epsilon /3$
• D. zero

Answer 1

The correct option is D zero

In steady state condition, current will not pass through the branch containing the capacitor as capacitor will behave like an open switch. Hence we can remove the capacitors and the circuit can be redrawn as

There is no current drawn from the battery as circuit is open. Therefore the potential difference between A and B is zero.