Question

Consider the circuit shown in figure. Switch S is closed at for t < 0, and steady state conditions are established. Switch is then opened at t = 0. Immediately after opening switch, choose the correct options.

• A. Current in branch BC is $\frac{3V}{8R}$
• B. Current in branch AB remains same in magnitude and direction.
• C. Potential difference across $L_2$ is V
• D. Current through $L_2$ is $\frac{3V}{8R}$

Answer 1

Answer: (A), (C)

The correct options are
A Current in branch BC is $\frac{3V}{8R}$
C Potential difference across $L_2$ is V

Current through $L_1$ and $L_2$ does not change just after opening switch. Then using junction law at D and by K.L.L we find p.d across $L_2$ and $L_1$