Question

Consider the circuit shown in the figure below.

BJT has $\beta =100,V_{BE}=0.7V.$ The value of $V_{CE}$ is

• A. 1.24 V
• B. 1.45 V
• C. 1.52 V
• D. 1.31 V

Answer 1

The correct option is D 1.31 V

$5-5k{I}_E-200k{I}_B-0.7=0$

$4.3=(505k+200k)I_B$
$I_B=0.068mA$
$I_E=0.616mA$
$I_C=0.609mA$
$5-5k{I}_E-1k{I}_C-V_{CE}=0$
$V_{CE}=1.31V$