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Question

# Consider the circuit shown in the figure below: Both the transistors are matched with IS1=IS2=4×10−16 A and VA=∞. If base current for transistor T1 is 15.625 μA and base current of T2 is very small compared to emitter and collector current, then the values of β for the transistors is approximately equal to (Assume VT=25.9 mV

A
150
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B
117
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C
189
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D
126
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Solution

## The correct option is B 117Drawing the Thevenin's equivalent circuit of the source, we get Since the transistors are perfectly matched VBE1=VBE2=VBE ∴ 2VBE1=1.6 V−5.76×103×15.625×10−6 =1.51 V Thus, VBE1=1.512=0.755 V Thus, IC=Isexp(VBEVT) 4×10−16exp(0.7550.0259) =1.828×10−3 A ∴ β=ICIB=1.82815.625×103=117

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