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Question

Consider the circuit shown in the figure below:

Both the transistors Q1 and Q2 are matched with β=50. The value of VBE=0.7 V, the value of current I0 is equal to ____ mA
  1. 0.241

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Solution

The correct option is A 0.241

The circuit can be redrawn as

For current mirror circuit,

Ireff=VCCVBER=100.737×103=0.251 mA


Now,

IG=Ireff(1+2β)=0.2511+250=0.241 mA


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