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Question

Consider the circuit shown in the figure below.

When the transistor is biased in active region,the value of voltage |VBE| = 0.7 V. Then the value of power dissipated by the transistor is equal to _____ mV.
  1. 5.028

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Solution

The correct option is A 5.028

Assuming the transistor to be in active region, we get,

IC=αIE=β1+βIE=6061×0.61×103

=0.6 mA

Now, the voltage at VC=10+4.7×0.6=7.18 V

Value of IB=ICβ=0.660×103=1×105A=10 μA

now, VB=IBRB

=10×106×50×105=0.5 V

VE=VB+VEB=0.5+0.7=1.2 V

VEC=1.2(7.18)=8.38 V

Power dissipated VEC×IC=8.38×0.6×103=5.028 mW


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