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Question

Consider the circuit shown in the figure below:


In the circuit the maximum power rating of the zener diode is equal to 400 mW, the maximum possible value of RL is equal to ________ kΩ

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Solution

The correct option is A 1

Applying KCL at node 'A' , we get,IS=Iz+ILIz(max)=P2(max)Vz=400×10310=40mAnow,Is=VsVzRs=2010200=10200=50mAIL(nin)=IsIz(max) IL(min)=10×103=10mARL(max)=VzIL(max)=1010×103=1kΩ

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