Question

For the given circuit, the power across zener diode is ____$\text{mW}$.

Answer 1

Since, the potential difference across the load resistance is $10\text{V}$, the current through $R_L$ is given by,

$i=\frac{10\text{V}}{5\text{k}\Omega }=2\text{mA}$

Using voltage divider rule, current through $1\text{k}\Omega$ resistor can be given by,

$I=\frac{14\text{V}}{1\text{k}\Omega }=14\text{mA}$

Using $\text{K.C.L}$ we have,

$I_Z=I-i$

$\Rightarrow I_Z=14-2=12\text{mA}$

$\therefore P=I_Z{V}_Z=12\times 10=120\text{mW}$