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Byju's Answer
Standard XII
Mathematics
Complex Numbers
Consider the ...
Question
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then
complex number
z
1
¯
¯
¯
z
2
is,
A
purely real
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B
purely imaginary
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C
zero
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D
none of these
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Solution
The correct option is
B
purely imaginary
|
z
1
|
2
+
|
z
2
|
2
=
|
z
1
+
z
2
|
2
|
z
1
+
z
2
|
2
=
(
z
1
+
z
2
)
(
¯
z
1
+
¯
z
2
)
⟹
|
z
1
|
2
+
|
z
2
|
2
=
(
z
1
+
z
2
)
(
¯
z
1
+
¯
z
2
)
⟹
|
z
1
|
2
+
|
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
+
z
1
¯
z
2
+
z
2
¯
z
1
⟹
z
1
¯
z
2
+
z
2
¯
z
1
=
0
⟹
z
1
¯
z
2
+
¯
z
1
z
2
=
0
⟹
R
e
(
z
1
¯
z
2
)
=
0
..{
∵
z
+
¯
z
=
2
R
e
(
z
)
}
∴
z
1
¯
z
2
is purely imaginary.
Ans: B
Suggest Corrections
0
Similar questions
Q.
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then
one of the possible argument of complex number
i
z
1
z
2
is,
Q.
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then the p
ossible difference between the argument of
z
1
and
z
2
is,
Q.
If
z
1
and
z
2
are complex numbers and
u
=
√
z
1
z
2
, then prove that
|
z
1
|
+
|
z
2
|
=
∣
∣
∣
z
1
+
z
2
2
+
u
∣
∣
∣
+
∣
∣
∣
z
1
+
z
2
2
−
u
∣
∣
∣
.
Q.
If
z
1
and
z
2
are complex numbers and
u
=
√
z
1
z
2
,
then
∣
∣
∣
z
1
+
z
2
2
+
u
∣
∣
∣
+
∣
∣
∣
z
1
+
z
2
2
−
u
∣
∣
∣
is equal to
Q.
If
z
1
,
z
2
are two complex numbers such that
|
z
1
|
=
|
z
2
|
=
2
and
arg
z
1
+
arg
z
2
=
0
then
z
1
z
2
=
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