Consider the composite system shown in the figure which is held at 300 K. Assuming ideal gas behavior, calculate the total pressure if the barriers separating the compartments are removed. Assume that the volume of the barriers is negligible. (Given: R = 0.082 atm L−1mol−1k−1 )
2 atm
Hence, P1=1.5 atm,V1=2 L
P2=2.5 atm,V2=4 L
P3=1 atm,V3=1 L
Now, P1V1+P2V2+P3V3=P4V4
Here, V4 = Total volume = 2 + 4 + 1 = 7 L & PT=P4
Now, 2×1.5 + 4×2.5 + 1×1=7×PT
⇒PT=2atm.