Consider the compounds, $B C l_{3}$ and $C C l_{4}$ . How will they behave with water? Justify.

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Solution

Being a Lewis acid, $B C l_{3}$ readily undergoes hydrolysis. Boric acid is formed as a result.
$B C l_{3} + 3 H_{2} O ⟶ 3 H C l + B (O H)_{3}$
$C C l_{4}$ completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When $C C l_{4}$ and water are mixed, they form separate layers.
$C C l_{4} + H_{2} O ⟶ N o r e a c t i o n$

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